Question 1128279
Hi

This one is pretty tough!!!!

a) for the elements of the sample space surely they are 1 2 3 4 5 for the tickets and 1 2 3 4 5 6 for the dice
b) Ok for you to get an even number it is either even + even or odd + odd so

First part - Tickets
Chance of drawing even is 2/5
Chance of drawing odd is 3/5

Second part - dice
Chance of throwing even 3/6
Chance of throwing odd 3/6

So 2/5 x 3/6 and 3/5 x 3/6
2/5 x 3/6 = 1/5
3/5 x 3/6 = 3/10

1/5 + 3/10 = 1/2

So there is a 50% chance - However you could have just said if it isn't even then it is odd which would have been a lot more simple!!

c) Right ok for this one
You have a choice of 5 in the first part - 1 2 3 4 5
You have a choice of 6 in the second part - 1 2 3 4 5 6 

If you pick 1 for example you have a 1/5 chance of selecting 1 the first time and a 1/6 chance in the second part so multiply 1/5 x 1/6 = 1/30

That is the probability for selecting two of the same.

Hope this has been of some help