Question 102471
Is this what you mean?
{{{sqrt(16z^12)=(16z^12)^(1/2)}}} The square root means raised to the power of 1/2.
When you have an exponent expression raised to a power, you multiply the exponents, such as
{{{(x^m*y^p)^n = x^(m*n)*y^(p*n)}}}
Back to your problem
{{{sqrt(16z^12)=(16z^12)^(1/2)}}}
{{{sqrt(16z^12)=16^(1/2)*z^(12*(1/2))}}}
{{{sqrt(16z^12)=4z^(6)}}}