Question 1128269
What is the base?  2, 10, 5, what?  Something else?


OKay need not be given the base.

{{{log((2+x))+log((x-2))=log((5))}}}--------note: this very first line is a mistake, 


therefore all of this is still wrong:
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{{{log((x^2-4))=log((5))}}}

arguments must be equal.

{{{x^2-4=5}}}

{{{x^2=9}}}

{{{x=3}}}
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The original equation shows MINUS of a log; not the PLUS of a log.

First two steps should have been:

{{{log(((2+x)/(x-2)))=log((5))}}}


{{{(2+x)/(x-2)=5}}}

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