Question 102380
The height of an object thrown upward with an initial velocity of 134 feet per second is given by the formula h = -16t2 + 134t, where t is the time in seconds. How long will it take the object to reach a height of 67 feet? 
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Let h = 67 and solve for "t".
-16t^2+134t-67 = 0
Use the quadratic formula to get:

t = [-134 +- sqrt(134^2-4*-16*-67)]/(-32)

t = [-134 +- sqrt(13668)]/(-32)

t = [-134 +- 116.91]/(-32)

t = 7.841 (time on the way down to the ground)
 or t=0.534 (time on the way up from the ground)

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Cheers,
Stan H.