Question 1128151
log(x^3-1)=log(x^2+x+1)
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Since the logs are equal:
x^3-1 = x^2+x+1
{{{x^3 - x^2 - x - 2 = 0}}}
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{{{(x-2)*(x^2 + x + 1) = 0}}}
x = 2, the only real root