Question 1128086
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Let x = the number of $10 tickets.


Then the number of the $20 tickets is (x+191),

and the number of the $30 tickets is  (3281- x - (x+191)) = (3090-2x).


The "money" equation (the revenue equation) is 


    10x + 20*(x+191) + 30*(3090-2x) = 64510    dollars


Simplify and solve for x:


    10x + 20x + 20*191 - 60x + 30*3090 = 64510

    -30x = 64510 - 20*191 - 30*3090 

    -30x = -32010    ====>  x = {{{32010/30}}} = 1067.


<U>Answer</U>.  1067 of the $10 tickets;  (1067+191) = 1258 of the $20 tickets;  and  (3090-2*1067) = 956 of the $30 tickets.


<U>Check</U>.   1067*10 + 1258*20 + 956*30 = 64510  dollars.    ! Correct !
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Solved.


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For what reason @Mtrkcrc wrote his post and what does it mean is a mystery for me.


In my view, the reader can safely re-direct it into the TRASH section.