Question 102454
if the consecutive even integers are:
{{{2x }}} and {{{2x+2}}} 

then:
{{{2x + 5 = (1/2)*(2x+2)}}}
{{{2x + 5 = (x+1) }}}
{{{2x = x -4}}}
{{{2x -x = -4 }}}
{{{x = -4}}}

so
{{{2x = -8}}}    (this is smaller eveninteger)

and
{{{(2x+2)= -6}}}     (this is greater even integer)

since {{{(1/2)}}} of {{{-6}}} is equal to {{{-3}}}

then {{{-(3+5)=-8}}}