Question 1128116
the slope of the line is 7/5, so the slope of the line perpendicular to it is -5/7, the negative reciprocal.
point slope formula y-y1=m(x-x1), m slope, (x1, y1) point
y-3=(-5/7)(x-2)
y-3=-(5/7)x+10/7
y=(-5/7)x+31/7
{{{graph(300,300,-10,10,-10,10,(7/5)x+4,(-5/7)x+31/7)}}}