Question 102354
Consecutive even integers follow the form: {{{2x}}}, {{{2x+2}}}, {{{2x+4}}}, ...., etc.



So the product of four consecutive even integers is:


{{{2x+(2x+2)+(2x+4)+(2x+6)=308}}}



{{{8x+12=308}}} Combine like terms on the left side



{{{8x=308-12}}}Subtract 12 from both sides



{{{8x=296}}} Combine like terms on the right side



{{{x=(296)/(8)}}} Divide both sides by 8 to isolate x




{{{x=37}}} Divide


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Answer:

So our answer is {{{x=37}}} 





That means our first number is....


{{{2(37)=74}}}


So our first number is 74



Our second number is simply 2 more than 74


{{{74+2=76}}}


So our second number is 76




Our third number is simply 2 more than 76


{{{76+2=78}}}


So our third number is 78



Our fourth number is simply 2 more than 78


{{{78+2=80}}}


So our fourth number is 80




So our 4 consecutive even integers are 


74,76,78, and 80



Check:


{{{74+76+78+80=308}}}



{{{308=308}}} works