Question 1128008
the equation of the line, in slope-intercept form, that satisfies the given conditions. 
The graph is perpendicular to the graph of 

{{{y = 5x - 1}}}-> slope {{{m=5}}}

perpendicular lines have slopes negative reciprocal to each other, so 
perpendicular line will have a slope {{{-1/5}}}

so far, equation is:

{{{y=-(1/5)x+b}}}

and if passes through the point whose coordinates are 
({{{2}}}, {{{-2}}}), we have

{{{-2=-(1/5)2+b}}}

{{{-2=-(2/5)+b}}}

{{{-2+(2/5)=b}}}

{{{b=-10/5+2/5}}}

{{{b=-8/5}}}

and, equation is: {{{y=-(1/5)x-8/5}}}

{{{drawing ( 600, 600, -10, 10, -10, 10,
circle(2,-2,.12),locate(2,-2,p(2,-2)),
graph( 600, 600, -10, 10, -10, 10, 5x-1, -(1/5)x-8/5)) }}}