Question 1128025
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<pre>
Let D be the distance to travel, in miles.


Then the time traveling at the speed of 60 mph is  {{{D/60}}} hours,

while the time traveling at the speed of 45 mph is  {{{D/45}}} hours. 


We are given that the difference  {{{D/45}}}  - {{{D/60}}}   is 10 minutes - 5 minutes = 5 minutes = {{{1/12}}} of an hour:


    {{{D/45}}}  - {{{D/60}}}  = {{{1/12}}}.


<U>It is your basic equation</U>, and <U>the setup is just DONE</U>.


To solve the equation, multiply its both sides by  180.  You will get


    4D - 3D = 15,

    D = 15    miles.


The appointment is scheduled at  {{{15/60}}} hours + 10 minutes = 15 minutes + 10  minutes = 25 minutes counting from the time

the executive starts his journey.
</pre>

Solved.


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To see other similar solved problems, &nbsp;look into the lesson

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=http://www.algebra.com/algebra/homework/word/travel/How-far-do-you-live-from-school.lesson>How far do you live from school?</A> 

in this site.


Your problem is non-standard and is different from that usually are offered in typical Math classes.


Since you are interested in such kind of problems, &nbsp;I recommend you to look into my other lessons on Travel & Distance 
that you will find in accompanied references to that lesson.


You will find there &nbsp;<U>A &nbsp;LOT</U>&nbsp; of &nbsp;<U>unique</U>&nbsp; and &nbsp;<U>interesting</U>&nbsp; &nbsp;<U>non-standard</U>&nbsp; Travel & Distance  problems.