Question 1127979
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Algebraically, we can let x be the amount invested at 2%; then (8000-x) is the amount invested at 3%.  Then since the amounts of interest are the same,<br>
{{{.02(x)= .03(8000-x)}}}<br>
That equation is easily solved using basic algebra.  I'll let you finish.<br>
Here is a different way to solve the problem informally, using ratios and logical reasoning.<br>
Since the ratio of the interest rates is 2:3 and the amounts of interest are the same, the money must be invested in the ratio 3:2.  The ratio 3:2 means 3/5 of the money is invested at the lower rate and 2/5 of it at the higher rate.<br>
ANSWER: 3/5 of $8000 = $4800 at 2%; 2/5 o $8000 = $3200 at 3%.