Question 1127738
if a permutation of the word "white" is selected at random, 
find the probability that the permutation 
<pre>
The denominator of each of the probabilities will be 5P5 = 5! = 120
</pre>
A) begins with a consonant
<pre>
Pick the 1st letter any of 3 ways (w, h or t)
Arrange the remaining 4 letters in 4P4 = 4! = 24 ways

That's 3&#8729;24 = 72 ways

Probability = 72/120 = 3/5
</pre>
B) ends with a vowel
<pre>
Pick the 5th letter either of 2 ways (i or e)
Arrange the remaining 4 letters in 4P4 = 4! = 24 ways

That's 2&#8729;24 = 48 ways

Probability = 48/120 = 2/5
</pre>
C) has the consonants and vowels alternating
<pre>
CVCVC

The 3 consonants can be rearranged in the 1st, 3rd, and 5th
positions in 3P3 = 3! = 6 ways.
The 2 vowels can be rearranged in the 2nd and 4th
positions in 2P2 = 2! = 2 ways.

That's 6&#8729;2 = 12 ways

Probability = 12/120 = 1/10

Edwin</pre>