Question 1127938


the cliff {{{250m }}} high
the angle of depression to the boat farther away from Elizabeth is {{{57}}} degrees, 
its angle of elevation is the same
you need to find the length of the horizontal leg of the triangle

use {{{tan (57) = 250m/x}}}, which when solved for {{{x}}} is
{{{x=250/tan( 57)}}}
{{{x=250/1.54}}}
{{{x=162.34m}}}

and  the angle of depression to the nearer boat is {{{68}}}deg 

 {{{tan (68) = 250m/x}}}, which when solved for {{{x }}}is
{{{x=250/tan( 68)}}}
{{{x=250/2.48}}}
{{{x=100.81m}}}

distance between two boats is: {{{d=162.34m-100.81m=61.53m}}}