Question 102446
f(x) = 2x(x^2-4) = 2x^3-8x
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The polynomial you want is 2x^3-8x
which factors as 2x(x^2-4) = 2x(x-2)(x+2)
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How do you contruct it?
Take the product of any monomial and a factorable binomial.
Eg: 7x(x^2-9) or 3x(x^2-16) etc.
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Cheers,
stan H.