Question 1127885


Line {{{L}}} is perpendicular to a line with slope {{{m= 4/5}}}. 

Both lines contain the origin. ->({{{0}}},{{{0}}})

{{{y=mx+b}}}-> {{{b=0}}} -lines contain the origin

{{{y=(4/5)x}}}=> a line with slope {{{m= 4/5}}}

since line {{{L}}} is perpendicular to this line, it will have a slope 

{{{m[p]=-1/m}}}

{{{m[p]=-1/(4/5)}}}

{{{m[p]=-5/4}}}

{{{y=-(5/4)x}}}=>line {{{L}}} 

{{{ graph( 600, 600, -10, 10, -10, 10, (4/5)x, -(5/4)x) }}}