Question 1127789
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The number 10^2016 is 1 followed by 2016 zeros; a 2017-digit number.<br>
When you subtract 2016 from that number, you get a 2016-digit number.  In that number, the last four digits are 7984; the first 2012 digits are all 9's.<br>
The sum of the digits is<br>
{{{2012*9 + (7+9+8+4) = 18108+28 = 18136}}}