Question 1127767


{{{tan(theta) = a/b}}} then

{{{sin(theta)/cos(theta) = a/b}}}

=>

{{{sin(theta) = a }}}

{{{cos(theta)=b}}}

{{{sec (theta)= 1/cos(theta)=1/b}}}

{{{csc(theta) = 1/sin(theta)=1/a}}}