Question 1127758
The seventh term of the GP 

{{{a[1]=16/9}}}

{{{a[2]=-8/3}}}

{{{a[3]=4 }}}

find common ratio:


{{{r=a[2]/a[1]}}}


{{{r=(-8/3)/(16/9)}}}


{{{r=(-3/2)}}}



{{{a[n]=a[1]*r^(n-1)}}}


{{{a[n]=(16/9)*(-3/2)^(n-1)}}}


if you need the seventh term, means {{{n=7}}}

{{{a[7]=(16/9)*(-3/2)^(7-1)}}}

{{{a[7]=(16/9)*(-3/2)^6}}}

{{{a[7]=81/4}}}