Question 1127694

In triangle {{{ABC}}}:

{{{ a= sqrt(2)}}}, 
{{{b =1}}} 
measure angle {{{A =90}}}°  

Find the measure of angle {{{B}}}.

{{{A =90}}} triangle {{{ABC}}} is right angle triangle; 

so, since  
{{{ a= sqrt(2)}}}, 
{{{b =1}}} 

=>{{{c=1}}}

since {{{b =1}}} and {{{c=1}}}, we have isosceles right triangle and angles {{{B}}} and {{{C}}} are same and each measures {{{45}}}°


check:angle {{{B}}}

{{{sin(A)/a=sin(B)/b}}}

{{{sin(90)/sqrt(2)=sin(B)/1}}}

{{{1/sqrt(2)=sin(B)}}}

{{{B=sin^-1(1/sqrt(2))}}}

{{{B=45}}}°