<PRE><B>Question 1127601</B>
&lt;br&gt;
In the answer from the other tutor, they started on the problem by finding the constant of variation, using the given information.&lt;br&gt;
But then they didn&#39;t answer the question....&lt;br&gt;
That would have been a valid approach to solving the problem.  And it would have been an appropriate method if you need to get a complete formula for the volume, including the constant of variation  -- for example, if you needed a formula to use for finding the volume of several cones.&lt;br&gt;
But, in this problem, you only need to find the volume of one other cone.  The easiest way to do that is by looking at how each variable changes.&lt;br&gt;
The problem says the volume varies jointly as the height and the square of the radius.&lt;br&gt;
From the first cone to the second, the radius doesn&#39;t change at all, so the only change in the volume will be due to the change in height.&lt;br&gt;
From the first cone to the second, the height changes from 6 to 10, and increase by a factor of 10/6 = 5/3.&lt;br&gt;
So the volume will increase by that same factor.&lt;br&gt;
{{{(32pi)*(5/3) = (160/3)pi}}}&lt;br&gt;
The volume of the second cone is 160/3 pi.</PRE>