Question 1127528
To do this, you take the function and plug {{{-x}}} in for {{{x}}}, and then {{{simplify}}}. 
If you end up with the exact same function that you started with (that is, if {{{f (-x) = f (x)}}}, so all of the signs are the same), then the function is {{{even}}}. 
If you end up with the exact opposite of what you started with (that is, if {{{f (-x) = -f (x)}}}, so all of the signs are switched), then the function is {{{odd}}}.

In all other cases, the function is "{{{neither}}} even nor odd".



{{{f(x) = x^3 - 2 x + 1 }}}
{{{f(-x) = (-x)^3 - 2 (-x) + 1 }}}
{{{f(-x) = -x^3 + 2 x + 1}}} 
{{{f (-x) <> f (x)}}} =>is not an {{{even}}} function


check if {{{f (-x) = -f (x)}}}

{{{f(-x) = -(x^3 -2 x + 1) 
{{{f(-x) = -x^3 +2 x - 1 }}}

so, {{{f (-x)<> -f (x)}}} =>is not an {{{odd }}} function


so, answer is: {{{neither}}}