Question 1127482
A long distance runner started on a course running at an average speed of 6 mph. One hour later, a second runner began the same course at an average speed of 8 mph.
 How long after the second runner started will the second runner overtake the first runner?
:
let t = 2nd runner's time when overtaking the 1st runner
then
(t+1) = 1st runner's time
:
When the 2nd runner catches the 1st, they will have traveled the same distance.
write a distance equation; speed * time
8t = 6(t+1)
8t = 6t + 6
8t - 6t = 6
2t = 6
t = 6/2
t = 3 hrs for the 2nd runner to catch the 1st.