Question 1127445

 use the area formula.
{{{s = (1/2)(14+48+50) = 56}}}

area of the triangle {{{A= sqrt(s(s-a)(s-b)(s-c)) = sqrt(56*6*8*42) =336}}}

Also, area{{{A=(1/2)50*h*2 = 50h}}},

{{{h}}} is the answer or the perpendicular distance from midpoint of "side {{{14}}}" to "side {{{50}}}"

The line segment connecting the midpoint to the vertex divides the triangle to two equal halves.

Thus, 

{{{50h= 336}}} 

{{{h = 168/25}}} 

{{{h}}} = {{{6}}}{{{18/25}}}