Question 1127438
3{{{(2^2x+3)}}}-5{{{(5^2x+2)}}}-156=0
3(4x+3)-5(25x+2)-156=0
(12x+9)-125x-10-156=0
-113x-1-156=0
-113x-157=0
-113x=157
x=-1.389380531
Answer: x=-1.389
Hope this helps!