Question 1127337
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*[tex \LARGE \ \ \ \ \ \ \ \ \ \ a^2\ -\ \frac{1}{a}\ =\ 1]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ a^3\ -\ 1\ =\ a]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ a^3\ =\ a\ +\ 1]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ a^6\ =\ a^2\ +\ 2a\ +\ 1]


But


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ -\frac{1}{a}\ =\ 1\ -\ a^2]


So


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ a^6\ -\ \frac{1}{a}\ =\ a^2\ +\ 2a\ +\ 1\ +\ 1\ -\ a^2\ =\ 2a\ +\ 2]
								
								
John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
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*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \  
								
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