Question 1127310
using a(t) = -32ft/s^2
a(t) = -32ft/s^2 --> v(t) = ∫-32dt --> v(t) = -32t + C
v(0) = 72 --> v(0) = -32(0)+C = 72 so our velocity function is:
v(t) = -32t+72 --> at the maximum height the velocity will be zero, so we can restate:
0 = -32t+72 --> t = 2.25 
Now, to find the maximum height
s(t) = ∫v(t)dt = ∫(-32t+ 72)dt =
sorry I've run out of time. Maybe the above will help you find the answer