<PRE><B>Question 1127308</B>
The sum of two numbers is 20. The difference between three times the first number and twice the second is 40. What are the two numbers ?
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Equations::
x + y = 20
3x-2y = 40
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Solving by substitution::
x = 20-y
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So, 3(20-y)-2y = 40
60-5y = 40
5y = 20
y = 4
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Then x = 20-y = 16
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Cheers,
Stan H.
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