Question 1127308
The sum of two numbers is 20.
a + b = 20
 The difference between three times the first number and twice the second is 40.
3a - 2b = 40
 What are the two numbers?
Multiply the 1st equation by 2, add to the 2nd equation
2a + 2b = 40 
3a - 2b = 40
----------------addition eliminates b, find a
5a + 0 = 80
a = 80/5
a = 16
find b
 16 + b = 20
 b = 20 - 16
 b = 4 
:
;
Check in the 2nd equation
3(16) - 2(4) =
48 - 8 = 40