<PRE><B>Question 1127310</B>
Assume the acceleration of the object is a(t) = &amp;#8722;32 feet per second per second. (Neglect air resistance.)
A ball is thrown vertically upward from a height of 5 feet with an initial velocity of 72 feet per second. How high will the ball go? 
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Height equation::
h(t) = -32t^2+72t+5
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Maximum height occurs when t = -b/(2a) = -72/(2*-32) = 1.125
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h(1.125) = -32(1.125)^2 + 72(1.125)+5 = 45.5 ft
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Cheers,
Stan H.
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