Question 1127304
{{{ x^2 + 5x - 50 = 0 }}}
{{{ x^2 + 5x + (25/4) - 50 = 25/4 }}}
{{{ x^2 + 5x + (25/4)  = 25/4 + 50 }}}
{{{ (x + 5/2)^2 = 225/4 }}}  
{{{  (x+5/2) = +- 15/2 }}}   <— introduce +/- after sqrt of both sides
{{{  x = -5/2 +- 15/2  }}}

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Ans:  {{{ highlight( x = 5 ) }}}  and {{{ highlight( x = -10) }}} are the two solutions
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Check:
x=5:  5^2 + 5(5) - 50 = 25+25-50 = 0  (ok)
x=-10:  (-10)^2 + 5(-10) - 50 =  100 - 50 - 50 = 0  (ok)