Question 1127284
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<pre>

For any polynomial with real coefficients, the roots go in pairs (complex number, conjugate complex number).


Therefore, at given condition, the roots of the polynomial are  -2, 2-i  and 2+i,

and one possible polynomial is THIS


    f(x) = (x+2)*(x-(2-i))*(x-(2+i)), which is the same as


    f(x) = (x+2)*((x-2)+i)*((x-2)-i) = (x+2)*((x-2)^2+1).
</pre>


For your safety, &nbsp;ignore the post by &nbsp;@josgarithmetic, since it is &nbsp;&nbsp;<U>W R O N G</U>, &nbsp;&nbsp;as usual.