Question 1127249

C(10,3)*C(12,3) = number of committees with 3 men and 3 women
+C(10,2)*C(12,4) = number of committees with 2 men and 4 women
+C(10,1)*C(12,5) = number of committees with 1 man and 5 women
+C(10,0)*C(12,6) = number of committees with no men and 6 women
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= (120)*(220) + (45)*(495) + (10)*(792) + (1)*(924)
= 26400 + 22275 + 7920 + 924
= {{{ highlight( 57519 ) }}}  ways<br>

(assuming I haven't made an error in the calculations)
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