Question 1127229
 a box contains 77 coins, only dimes and nickels. The amount of money in the box is $5.25. How many dimes and how many nickles are in the box? 
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Quantity Equation: n + d = 77 coins
Value Equation:: 5n + 10d = 525 cents
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Solve for n and d::
5n + 5d = 5*77
5n + 10d= 525
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Subtract and solve for "d
5d = 525-385
5d = 140
d = 28 (# of dimes)
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Solve for "n"::
n = 77-d = 49 (# of nickels)
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Cheers,
Stan H.
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