Question 1127218


{{{-x+6y=1}}}...eq.1
{{{x+6y=2}}}.....eq.2
------------------------add eq.1 and eq.2

{{{-x+6y+x+6y=1+2}}}

{{{-cross(x)+12y+cross(x)=3}}}

{{{12y=3}}}


{{{y=3/12}}}.......simplify

{{{y=1/4}}}

go to {{{x+6y=2}}}.....eq.2 substitute {{{y}}}

{{{x+6(1/4)=2}}}

{{{x+(3/2)=2}}}

{{{x=2-(3/2)}}}

{{{x=4/2-3/2}}}

{{{x=1/2}}}