Question 1127162
The cos is negative in both the
2nd and 3rd quadrants
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Between these two, the sin is
positive in the 2nd quadrant
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If {{{ cos( theta ) = -.6 }}} then
{{{ ( -.6 )^2 + ( .8 )^2 = 1^2 }}}
{{{ .36 + .64 = 1 }}}, so
{{{ sin( theta ) = .8 }}}
{{{ tan( theta ) = .8/(-.6) }}}
{{{ tan( theta ) = -4/3 }}}
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{{{ tan( theta ) + sin( theta ) = -4/3 + 4/5 }}}
{{{ tan( theta ) + sin( theta ) = -20/15 + 12/15 }}}
{{{ tan( theta ) + sin( theta ) = -8/15 }}}
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check the math