Question 1127191

the equation of the line, in standard form, that passes through 
({{{4}}}, {{{-3}}}) and is {{{parallel}}} to the line whose equation is {{{4x + y - 2 = 0}}}

recall: equations of the {{{parallel}}} lines have same slope

first write your equation in slope-intercept form 

{{{4x + y - 2 = 0}}}
{{{ y = -4x+2}}}-> slope is {{{-4}}}

equation of the {{{parallel}}} line will be:

{{{y=-4x+b}}}......use given point ({{{4}}}, {{{-3}}}) to find {{{b}}}

{{{-3=-4*4+b}}}

{{{-3=-16+b}}}

{{{16-3=b}}}

{{{b=13}}}

so, your line is {{{y=-4x+13}}}

write it in standard form

{{{4x+y=13}}}

and your answer is: B) {{{4x+y=13}}}



graph:


{{{drawing( 600, 600, -15, 15, -15, 15,
circle(4,-3,.12),locate(4,-3,p(4,-3)),
 graph( 600, 600, -15, 15, -15, 15, -4x+2, -4x+13)) }}}