Question 1127192

Given: 

{{{-2x + 3y = 18}}}

When {{{x=0}}},the value of {{{y}}} will be

{{{-2*0 + 3y = 18}}}

{{{ 3y = 18}}}

{{{ y = 18/3}}}

{{{ y = 6}}}


 When {{{y=0}}}, the value of {{{x}}}

{{{-2x + 3*0 = 18}}}

{{{-2x = 18}}}

{{{x = 18/-2}}}

{{{x = -9}}}


these solutions mean that a line crosses {{{x}}}-axis at {{{x = -9}}} and {{{y}}}-axis at {{{y = 6}}}, and these points are called x and y-intercepts

 your {{{x}}}- intercept is: ({{{-9}}}, {{{0}}}) 

 your {{{y}}}- intercept is: ({{{0}}}, {{{6}}}) 
 

{{{ graph( 600, 600, -15, 15, -15, 15,  2x/3 +6) }}}