Question 1127147
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|5x|+4=10



|a+1|=|a-8|
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Two very separate equations, not of a system.



{{{abs(a+1)=abs(a-8)}}}


(*)
{{{a+1=-a+8}}}
{{{2a=7}}}
{{{a=7/2}}}


(*)
{{{a+1=a-8}}}
no solution here


The only solution possible is  {{{a=7/2=3&1/2}}}




{{{graph(400,400,-5,8,-5,8,abs(x+1),abs(x-8))}}}




check:
{{{abs(3&1/2+1)=abs(3&1/2-8)}}}
{{{4&1/2=4&1/2}}}