Question 1127135
let's the smaller number be {{{x}}} and the greater number be {{{y}}}
 
if the smaller number is {{{3}}} less than the greater,we have

 {{{x=y-3}}}....eq.1

if the greater is decreased by twice the smaller, the result is {{{-5}}}, so we have

{{{y-2x=-5}}}....eq.2...substitute {{{x}}} from eq.1

{{{y-2(y-3)=-5}}}.......solve for {{{y}}}

{{{y-2y-6=-5}}}

{{{-y-6=-5}}}

{{{5-6=y}}}

{{{y=-1}}}


{{{x=-1-3}}}....eq.1

{{{x=-4}}}


the two numbers are:{{{-4}}} and {{{-1}}}