Question 102289
The shape of the pool, when seen from one end, is that of a trapezoid.
The dimensions of this trapezoid are:
{{{b[1] = 26}}}
{{{b[2] = 14}}}
{{{h = 24}}}
For a trapezoid, the area is given by:
{{{A = ((b[1]+b[2])/2)h}}}
You can find the volume of this pool by first finding the area of the trapezoidal-shaped end, then multliplying this by the length of the pool.
{{{V = ((b[1]+b[2])/2)h*L}}} Where:
L = length of pool = 32ft.
{{{V = ((26+14)/2)*24*32}}}
{{{V = (40/2)*24*32}}}
{{{V = 20*24*32}}}
{{{V = 15360}}}Cubic feet.