Question 1127075


{{{log(9, x )= -1/2}}}...change to base {{{10}}}

{{{log(x)/log(9)= -1/2}}}

{{{log(x)= -(1/2)log(9)}}}

{{{log(x)= log(9^(-1/2))}}}


{{{log(x)= log(1/9^(1/2))}}}

{{{log(x)= log(1/sqrt(9))}}}

{{{log(x)= log(1/3)}}}....since log same, we have

{{{x=1/3}}}