Question 1127028
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Same solution, basically, as the other tutor... but presented (I hope) so that the algebra is more clear....<br>
The width is x; the length is x+30.<br>
"If the length were increased by 50 and the width decreased by 8 (making the dimensions x-8 and x+80), the area would be 200 greater than originally"<br>
Algebraic translation:<br>
{{{(x-8)(x+80) = x(x+30)+200}}}
{{{x^2+72x-640 = x^2+30x+200}}}
{{{42x = 840}}}
{{{x = 20}}}<br>
The width is x = 20 feet; the length is x+30 = 50 feet.<br>
CHECK:
20*50 = 1000; (20-8)(50+50) = 12*100 = 1200