Question 1127051
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If the roots are in the ratio 2:3, then the equation in factored form can be written as<br>
{{{y = a(x-2n)(x-3n)}}}<br>
Expanding....<br>
{{{y = a(x^2-5nx+6n^2) = ax^2-5anx+6an^2}}}<br>
Then<br>
{{{6b^2 = 6(-5an)^2 = 6(25a^2n^2) = 150a^2n^2}}}
and
{{{25ac = 25(a)(6an^2) = 150a^2n^2}}}<br>