Question 1127049



The man's age now = {{{y}}}
His son's age now = {{{x}}} 

Three years from now:

 a man will be:{{{y+3}}}
 his son will be:{{{x+3}}}

since three years from now a man will be three times as old as his son will be, we have

{{{y+3=3(x+3)}}}...solve or {{{y}}}

{{{y=3x+9-3}}}

{{{y=3x+6}}}............eq.1


Two years ago: 
 
{{{y-2}}}
{{{x-2}}}

if he was four times as old as his son was,we have 

{{{y-2=4(x-2)}}}...solve or {{{y}}}

{{{y=4x-8+2}}}

{{{y=4x-6}}}...........eq.2

from eq.1 and eq.2 we have

{{{3x+6=4x-6}}}....solve or {{{x}}}

{{{6+6=4x-3x}}}

{{{x=12}}}

find {{{y}}}

{{{y=4*12-6}}}...........eq.2

{{{y=42}}}


The man's age now = {{{42}}}
His son's age now = {{{12}}}