Question 1127022

let three consecutive integers be {{{x}}},{{{(x+1)}}}, and {{{(x+2)}}}

If the second of three consecutive integers is subtracted from {{{105}}}, the result is the sum of the first and third:

{{{105-(x+1)=x+(x+2)}}}

{{{105-x-1=x+x+2}}}

{{{104-x=2x+2}}}

{{{104-2=2x+x}}}

{{{102=3x}}}

{{{x=102/3}}}

{{{x=34}}}-> first integer

{{{(x+1)=35}}}->second integer

{{{(x+2)=36}}}-> third integer


check:

{{{105-(x+1)=x+(x+2)}}}

{{{105-35=34+36}}}

{{{70=70}}}