Question 1126969

Let:
F = number of five peso coins
T = number of ten peso coins<br>

(1)  F + T = 10   (from "I have ten coins…")
(2)  5F + 10T = 70   (from "…these ten coins are worth 70…")<br>

5*(1) ==>  5F + 5T = 50

Subtract this from (2):
           0*F + 5T = 20  —>  T=4  —> F=6   —>  F-T = {{{ highlight( 2 ) }}}<br>

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Ans:  You have two more five peso coins (6) than ten peso coins (4).
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Check:  4*10 + 6*5 = 40 + 30 = 70 (ok)