Question 1126901
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Of course you should know how to solve a problem like this using formal algebra, as demonstrated in the response from tutor @boreal.<br>
But this is a good type of problem with which you can get some good mental exercise by solving it informally, using logical reasoning.<br>
And you also can see that the formal algebraic solution does nearly exactly the same thing as the informal solution to get the answer; that helps you see how the formal algebraic solution makes sense.<br>
(1) Imagine the coins on the table in front of you -- nickels and dimes with a total value of $1.45, with 4 more dimes than nickels.<br>
(2) Count the 4 "extra" dimes first.  That's 40 cents, leaving $1.05; and now the numbers of nickels and dimes are the same.<br>
(3) One nickel and one dime together make 15 cents; the number of nickels and dimes needed to make the remaining $1.05 (105 cents) is 105/15 = 7.<br>
So there are 7 nickels; the number of dimes is 7 plus the 4 you counted first, for a total of 11.<br>
ANSWER: 7 nickels, 11 dimes.<br>
If you are new to algebra and have trouble seeing why it works, compare this informal solution to the formal one provided by the other tutor; you will see that the calculations are the same in both.