Question 1126900
4 apples, 6 bananas, 5 pears, 1 orange.
total is 16 pieces of fruit.


probability of first piece to be a pear is 5/16.
since the fruit is replaced before picking again, the probability of the second piece being a pear is also 5/16.


the probability of both pieces being selected is 5/16 * 5/16 = 25/256.


here's a reference.


<a href = "https://www.mathsisfun.com/data/probability-events-conditional.html" target = "_blank">https://www.mathsisfun.com/data/probability-events-conditional.html</a>