Question 1126685
.
<pre>
2x +  y = 13,     (1)
4x + 5y = 11.     (2)


Multiply eq(1) by the factor 2 (both sides). Keep the equation (2) as is.  You will get an equivalent system


4x + 2y = 26      (1')
4x + 5y = 11      (2')


Now subtract  eq(1') from eq(2').  The terms "4x" will cancel each other,    (<<<---=== it is how the Elimination method works)
and you will get a single equation for the unknown "y"

5y - 2y = 11 - 26,   or

3y = -15,

which implies  y = -15/3 = -5.


Now from equation (1),  2*x - 5 = 13;  hence,  2x = 13 + 5 = 18   and  x = 18/2 = 9.


    Check the solution on your own by substituting the found values into the original equation.

    Do it on your own (I just did it mentally).


<U>Answer</U>  x= 9;  y= -5.
</pre>

Solved.


---------------


See the lesson

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF= http://www.algebra.com/algebra/homework/coordinate/lessons/Solution-of-the-lin-syst-of-two-eqns-with-two-unknowns-Elimination-method.lesson>Solution of the linear system of two equations in two unknowns by the Elimination method</A> 

in this site.